Σ_(i=1) ^6 f(i)=Σ_(i=1) ^6 f(6+1−i) Σ_(i=1) ^6 Σ_(j=1) ^i f(i,j)=Σ_(i=1) ^6 Σ_(j=1) ^i f(6+1−j,6+1−i) Σ_(i=1) ^6 Σ_(j=1) ^i Σ_(k=1) ^j f(i,j,k)=Σ_(i=1) ^6 Σ_(j=1) ^i Σ


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Question Number 196539 by qaz last updated on 27/Aug/23

$\underset{i = 1}{\sum^{6}} f (i) = \underset{i = 1}{\sum^{6}} f (6 + 1 - i)$ $\underset{i = 1}{\sum^{6}} \underset{j = 1}{\sum^{i}} f (i, j) = \underset{i = 1}{\sum^{6}} \underset{j = 1}{\sum^{i}} f (6 + 1 - j, 6 + 1 - i)$ $\underset{i = 1}{\sum^{6}} \underset{j = 1}{\sum^{i}} \underset{k = 1}{\sum^{j}} f (i, j, k) = \underset{i = 1}{\sum^{6}} \underset{j = 1}{\sum^{i}} \underset{k = 1}{\sum^{j}} f (?, ?, ?)$
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