Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 99575 by MWSuSon last updated on 21/Jun/20

$$\mathrm{if}\mathrm{a},\mathrm{b},\mathrm{c},\mathrm{d},\mathrm{e}\mathrm{are}\mathrm{in}\mathrm{AP}.\mathrm{find}\mathrm{the}\mathrm{value}$$$$\mathrm{of}\mathrm{a}-4\mathrm{b}+6\mathrm{c}-4\mathrm{d}+\mathrm{e}.$$$$\mathrm{please}\mathrm{help},\mathrm{i}\mathrm{do}\mathrm{not}\mathrm{know}\mathrm{where}\mathrm{to}$$$$\mathrm{begin}.$$

Answered by mathmax by abdo last updated on 21/Jun/20

$$\mathrm{take}\mathrm{a}\mathrm{try}\mathrm{first}...$$

Commented by MWSuSon last updated on 21/Jun/20

okay sir, although I've tried, but your comment gives me a little assurance that it looks easier than I think.

Commented by mathmax by abdo last updated on 21/Jun/20

$$\mathrm{perhaps}...$$

Commented by MWSuSon last updated on 22/Jun/20

$$\mathrm{a},\mathrm{b},\mathrm{c},\mathrm{d},\mathrm{e}$$$$\mathrm{b}=\mathrm{a}+\mathrm{k}$$$$\mathrm{c}=\mathrm{a}+2\mathrm{k}$$$$\mathrm{d}=\mathrm{a}+3\mathrm{k}$$$$\mathrm{e}=\mathrm{a}+4\mathrm{k}$$$$\mathrm{a}-4\mathrm{b}+6\mathrm{c}-4\mathrm{d}+\mathrm{e}$$$$(\mathrm{a}+\mathrm{e})+6\mathrm{c}-4(\mathrm{b}+\mathrm{d})$$$$=(2\mathrm{a}+4\mathrm{k})+6\mathrm{a}+12\mathrm{k}-4(2\mathrm{a}+4\mathrm{k})$$$$=0.$$$$\mathrm{Thank}\mathrm{you}\mathrm{sir},\mathrm{you}\mathrm{were}\mathrm{right},\mathrm{i}\mathrm{did}$$$$\mathrm{not}\mathrm{give}\mathrm{it}\mathrm{a}\mathrm{try}.$$

Answered by mathmax by abdo last updated on 22/Jun/20

$$\mathrm{b}=\mathrm{a}+\mathrm{r},\mathrm{c}=\mathrm{a}+2\mathrm{r},\mathrm{d}=\mathrm{a}+3\mathrm{r}\mathrm{and}\mathrm{e}=\mathrm{a}+4\mathrm{r}\Rightarrow$$$$\mathrm{a}-4\mathrm{b}+6\mathrm{c}-4\mathrm{d}+\mathrm{e}=\mathrm{a}-4\mathrm{a}-4\mathrm{r}+6\mathrm{a}+12\mathrm{r}-4\mathrm{a}-12\mathrm{r}+\mathrm{a}+4\mathrm{r}$$$$=0$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com