if y=x^3 +x^2 +3x.... find its turning point


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*Question Number 24598 by D¬ B£$T* last updated on 22/Nov/17**

$i f y = x^{3} + x^{2} + 3 x . . . .$ $f i n d i t s t u r n i n g p o i n t$
	Answered by jota+ last updated on 23/Nov/17

	$\frac{d^{2} y}{{d x}^{2}} = 6 x + 2 = 0$ $\Rightarrow x = - \frac{1}{3} .$
	Answered by mrW1 last updated on 23/Nov/17

	$\frac{d y}{d x} = 3 x^{2} + 2 x + 3 = 3 {(x + \frac{1}{3})}^{2} + \frac{8}{3} > 0$ $\Rightarrow t h e r e i s n o t u r n i n g p o i n t .$
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