lim_(x→∞) x^k e^(−4x) , k>0


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Question Number 76151 by Rio Michael last updated on 24/Dec/19

$\lim_{x \to \infty} x^{k} e^{- 4 x}, k > 0$
Commented by kaivan.ahmadi last updated on 24/Dec/19

${l i m}_{x - \to \infty} \frac{x^{k}}{e^{4 x}} = 0$
Commented by kaivan.ahmadi last updated on 24/Dec/19

$b y k + 1 d e r i v a t i o n t h e x^{k} i s 0$
Commented by kaivan.ahmadi last updated on 24/Dec/19

${l i m}_{x \to \infty} \frac{0}{4^{k + 1} e^{4 x}} = 0$
Commented by Rio Michael last updated on 24/Dec/19

$t h a n k s$
Commented by mr W last updated on 24/Dec/19

$i f k i s n o i n t e g e r, k + 1 t h d e r i v a t i o n$ $i s n o t z e r o .$
Commented by benjo last updated on 24/Dec/19

$yes sir . i agree$
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