All Questions Topic List
Algebra Questions
Previous in All Question Next in All Question
Previous in Algebra Next in Algebra
Question Number 12093 by uni last updated on 13/Apr/17
logabcb=3logabcc=4logabca=?
Answered by ajfour last updated on 13/Apr/17
logabcabc=(logabca)+(logabcb)+(logabcc)=1(logabca)+3+4=1logabca=−6.
Terms of Service
Privacy Policy
Contact: info@tinkutara.com