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Question Number 104835 by bemath last updated on 24/Jul/20
{logp(q)=x2logq(p3)=xfindx
Answered by john santu last updated on 24/Jul/20
{q=px2→qx=(px2)xp3=qx→p3=px.x2⇒x3=3;x=33(JS⊛)
Answered by Dwaipayan Shikari last updated on 24/Jul/20
logp(q)=x23logq(p)=x3logqp.logpq=x33=x3x=33
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