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Question Number 161362 by cortano last updated on 17/Dec/21
logx3(3x−54)log3(x)=18−3logx3(x2)x=?
Commented by bobhans last updated on 17/Dec/21
log3(x)[1+log3(x−18)]12[log3(x)−1]=18−6log3(x)log3(x)−12log3(x)[1+log3(x−18)]log3(x)−1=12log3(x)−18log3(x)−12log3(x)+2log3(x)log3(x−18)=12log3(x)−18log3(x)log3(x−18)−5log3(x)+9=0
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