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Question Number 145951 by ArielVyny last updated on 09/Jul/21
∑n⩾1(−1)nn=??
Answered by Olaf_Thorendsen last updated on 09/Jul/21
11+x=1−x+x2−x3+...=∑∞n=0(−1)nxnln∣1+x∣=∑∞n=0(−1)nxn+1n+1=−∑∞n=1(−1)nxnnifx=1∑∞n=1(−1)nn=−ln2
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