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Question Number 90038 by frc2crc last updated on 21/Apr/20

$$\underset{n=1}{\sum ^{\mathrm{\infty }}}\frac{H_n}{n^k}=S_k{H}_q=\underset{p=1}{\sum ^q}\frac{1}{p}$$$$Isthereasimplefromfor{S}_k$$

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