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Question Number 11343 by jaskaurrangerleader@gmail.com last updated on 21/Mar/17

$$n_{{\mathbf{c}}_{\mathbf{n}}}=\frac{n1}{(n-n)}$$

Commented by FilupS last updated on 21/Mar/17

$$\frac{n}{n-n}=\mathrm{undefined}$$

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