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Question Number 156240 by SANOGO last updated on 09/Oct/21
∫−π2π2∣sin(x)∣dx∫0π∣cos(x)∣dx
Commented by SANOGO last updated on 09/Oct/21
mercibienledur
Commented by tabata last updated on 09/Oct/21
youarewelcome
∫−π2π2∣sin(x)∣dx∣sin(x)∣isalwaysevenfunctionandsymetricaboutzero∴∫−π2π2∣sin(x)∣dx=2∫0π2∣sin(x)∣dxI=−2(cos(x))0π2=−2(−1)=2when:∫0π∣cos(x)∣dxalso=2⟨M.T⟩
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