prove that : 2^π >8


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Question Number 73523 by 01 last updated on 13/Nov/19

$prove that :$ $2^{π} > 8$
	Answered by MJS last updated on 13/Nov/19

	$3 < π \Rightarrow π = 3 + p; p > 0$ $2^{3 + p} > 2^{3}$ $2^{3} 2^{p} > 2^{3}$ $2^{p} > 1$ $p \ln 2 > 0$ $p > 0$ $true$
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