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Question Number 195038 by sciencestudentW last updated on 22/Jul/23

$$provethatx+y=\frac{1}{x-y}$$

Commented by Frix last updated on 22/Jul/23

$${\mathrm{It}}^{\prime }\mathrm{s}\mathrm{wrong},\mathrm{i}.\mathrm{e}.x=2\wedge y=3\Rightarrow$$$$x+y=5\mathrm{but}\frac{1}{x-y}=-1$$$$$$$$\mathrm{You}\mathrm{can}\mathrm{solve}\mathrm{for}x\mathrm{or}y$$$$x+y=\frac{1}{x-y}\Rightarrow x\ne y$$$$(x+y)(x-y)=1$$$$x^2-y^2=1$$$$x=\pm \sqrt{y^2+1}$$$$y=\pm \sqrt{x^2-1}$$

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