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Question Number 17100 by virus last updated on 30/Jun/17

$$\sec x\cos 5x+1=0$$$$findnumberofsolution$$

Answered by Tinkutara last updated on 01/Jul/17

$$\cos 5x+\cos x=0$$$$2\cos 3x\cos 2x=0$$$$\mathrm{Either}\cos 3x=0\mathrm{or}\cos 2x=0$$$$\Rightarrow x=(2n+1)\frac{\pi }{6}\mathrm{or}(2k+1)\frac{\pi }{4}$$$$\mathrm{There}\mathrm{should}\mathrm{be}\mathrm{infinite}\mathrm{number}\mathrm{of}$$$$\mathrm{solutions}.$$

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