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Question Number 178452 by cortano1 last updated on 16/Oct/22

$$\mathrm{show}\mathrm{that}$$$$((\mathrm{p}\wedge \mathrm{q})\Rightarrow \mathrm{r})\Rightarrow ((\mathrm{p}\wedge \sim \mathrm{r})\Rightarrow \sim \mathrm{q})$$$$\mathrm{is}\mathrm{tautology}$$

Answered by Spillover last updated on 17/Oct/22

Commented by cortano1 last updated on 17/Oct/22

$$\mathrm{nice}$$

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