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Question Number 21720 by Isse last updated on 01/Oct/17

$$\int {sin}^5\theta d\theta$$

Answered by sma3l2996 last updated on 02/Oct/17

$$=\int {(1-{cos}^{2}x)}^{2}sinxdx=\int (sinx-2{sinxcos}^{2}x+{sinxcos}^{4}x)dx$$$$=-cosx+\frac{2}{3}{cos}^{3}x-\frac{1}{5}{cos}^{5}x+C$$

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