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Question Number 88555 by M±th+et£s last updated on 11/Apr/20
slove⌈xa⌉<awhena>1⌈...⌉isceilfunction
Answered by mr W last updated on 11/Apr/20
⌈xa⌉=n<a⌈xa⌉=n<⌈a⌉−1xa⩽nx⩽na<(⌈a⌉−1)a⇒solutionisx<(⌈a⌉−1)a
Commented by M±th+et£s last updated on 11/Apr/20
godblessyousir
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