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Question Number 96883 by M±th+et+s last updated on 05/Jun/20
solvebysimpson′srule∫12.2ex2xdx
Commented by M±th+et+s last updated on 05/Jun/20
h=0.2ande=2.718
Commented by PRITHWISH SEN 2 last updated on 05/Jun/20
x=1,1.2,1.4,1.6,1.8,2.0,2.2I13=h3{(y0+y6)+4(y1+y3+y5)+2(y2+y4)}=0.23{(2.718+57.457)+4(3.516+8.082+27.287)+2(5.069+14.180)}=16.947
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