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Question Number 40544 by mondodotto@gmail.com last updated on 23/Jul/18

solve for x  3^((2x−1)) −4(3^x )+1=0

solveforx3(2x1)4(3x)+1=0

Answered by tanmay.chaudhury50@gmail.com last updated on 23/Jul/18

3^(2x) .3^(−1) −4.3^x +1=0  a=3^x   a^2 ×(1/3)−4a+1=0  a^2 −12a+3=0  a=((12±(√(144−12)) )/2)=((12±(√(132)) )/2)  a=((12±2(√(33)) )/2)=6±(√(33))  3^x =6±(√(33))   x=log_3 (6±(√(33)) )

32x.314.3x+1=0a=3xa2×134a+1=0a212a+3=0a=12±144122=12±1322a=12±2332=6±333x=6±33x=log3(6±33)

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