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Question Number 40544 by mondodotto@gmail.com last updated on 23/Jul/18
solveforx3(2x−1)−4(3x)+1=0
Answered by tanmay.chaudhury50@gmail.com last updated on 23/Jul/18
32x.3−1−4.3x+1=0a=3xa2×13−4a+1=0a2−12a+3=0a=12±144−122=12±1322a=12±2332=6±333x=6±33x=log3(6±33)
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