solve for x 4x=2^x


Question and Answers Forum

All Questions Topic List
None Questions
Previous in All Question Next in All Question
Previous in None Next in None
Question Number 34792 by mondodotto@gmail.com last updated on 11/May/18

$solve for x$ $4 x = 2^{x}$
	Answered by Joel579 last updated on 11/May/18

	Commented by Joel579 last updated on 11/May/18

	$Real solution$ $x = 0.3099$ $x = 4$
	Answered by mr W last updated on 13/Jan/19
	$4x=e^(xln 2) xe^(−xln 2) =(1/4) (−xln 2)e^(−xln 2) =−((ln 2)/4) ⇒−x ln 2=W(−((ln 2)/4)) ⇒x=−((W(−((ln 2)/4)))/(ln 2))= { ((−((−0.2148)/(ln 2))=0.3099)),((−((−2.7726)/(ln 2))=4)) :}$
	$4 x = e^{x \ln 2}$ ${x e}^{- x \ln 2} = \frac{1}{4}$ $(- x \ln 2) e^{- x \ln 2} = - \frac{\ln 2}{4}$ $\Rightarrow - x \ln 2 = W (- \frac{\ln 2}{4})$ $\Rightarrow x = - \frac{W (- \frac{\ln 2}{4})}{\ln 2} = {\begin{cases} - \frac{- 0.2148}{\ln 2} = 0.3099 \\ - \frac{- 2.7726}{\ln 2} = 4 \end{cases}$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum