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Question Number 172082 by Mikenice last updated on 23/Jun/22
solvelog0.52x+log0.5x−2<−0
Commented by mokys last updated on 23/Jun/22
log0.52x+log0.5x⩽22log0.5x+log0.5x⩽23log0.5x⩽2log0.5x⩽23x⩽(0.5)23⩽143anotherway:lnxln(0.5)⩽(23)⇒lnx⩽(23)ln(0.5)lnx⩽ln(0.5)23⇒x⩽(0.5)23⩽143Aldolaimy
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