solve ∣x^2 −4x−5∣=7


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Question Number 24662 by NECx last updated on 24/Nov/17

$s o l v e ∣ x^{2} - 4 x - 5 ∣= 7$
	Answered by mrW1 last updated on 24/Nov/17

	$x^{2} - 4 x - 5 = \pm 7$ $x^{2} - 4 x + 4 = 9 \pm 7$ ${(x - 2)}^{2} = 9 \pm 7$ ${(x - 2)}^{2} = 16 . . . (i)$ $x - 2 = \pm 4$ $x = 2 \pm 4 = - 2, 6$ ${(x - 2)}^{2} = 2 . . . (i i)$ $x - 2 = \pm \sqrt{2}$ $x = 2 \pm \sqrt{2} = 2 + \sqrt{2}, 2 - \sqrt{2}$
	Commented by NECx last updated on 24/Nov/17

	$t h a n k y o u v e r y m u c h s i r .$
	Commented by NECx last updated on 24/Nov/17

	$c a n t h e a n s w e r s f r o m a n a b s o l u t e$ $v a l u e a l s o b e r e p r e s e n t e d i n$ $i n t e r v a l s, i f s o p l e a s e h o w c a n t h e$ $a n s w e r b e r e p r e s e n t e d .$
	Commented by Joel578 last updated on 24/Nov/17

	$I think it {couldn}^{'} t$
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