Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 168878 by bounhome last updated on 20/Apr/22

solve: x^(2019) +x^(2020) +x^(2021) +x^(2022) =4

solve:x2019+x2020+x2021+x2022=4

Commented by bagjagugum123 last updated on 20/Apr/22

x=1

x=1

Commented by mathlove last updated on 20/Apr/22

x^(2019) +x^(2020) +x^(2021) +x^(2022) =1^(2019) +1^(2020) +1^(2021) +1^(2022) x=1

x2019+x2020+x2021+x2022=12019+12020+12021+12022x=1

Commented by MJS_new last updated on 20/Apr/22

x=1 x≈−1.0031931511975 and 2020 complex solutions

x=1x≈−1.0031931511975and2020complexsolutions

Answered by Rasheed.Sindhi last updated on 20/Apr/22

solve: x^(2019) +x^(2020) +x^(2021) +x^(2022) =4 (x^(2019) −1)+(x^(2020) −1) +(x^(2021) −1)+(x^(2022) −1)=0 (x−1)(...) +(x−1)(...) +(x−1)(...) +(x−1)(...) =0 (x−1)(...)=0 x−1=0 x=1

solve:x2019+x2020+x2021+x2022=4(x2019−1)+(x2020−1)+(x2021−1)+(x2022−1)=0(x−1)(...)+(x−1)(...)+(x−1)(...)+(x−1)(...)=0(x−1)(...)=0x−1=0x=1

Commented by mathlove last updated on 20/Apr/22

nice

nice

Terms of Service

Privacy Policy

Contact: info@tinkutara.com