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Question Number 107764 by hhryhrry2 last updated on 12/Aug/20

$$\tan \theta =\frac{\mathrm{\Sigma }{\mathrm{F}}_{\mathrm{y}}}{\mathrm{\Sigma }{\mathrm{F}}_{\mathrm{x}}}$$$$$$

Commented by ajfour last updated on 12/Aug/20

$$\frac{d\overline{p}}{dt}=\sqrt{{\left(\mathrm{\Sigma }{F}_x\right)}^2+{\left(\mathrm{\Sigma }{F}_y\right)}^2}(\cos \theta \hat{i}+\sin \theta \hat{j})$$

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