trace the curve y^2 (x+1)=x^2 (3−x) clearly stating all the properties used for tracing.


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Question Number 25656 by rita1608 last updated on 12/Dec/17

$t r a c e t h e c u r v e$ $y^{2} (x + 1) = x^{2} (3 - x)$ $c l e a r l y s t a t i n g a l l t h e p r o p e r t i e s u s e d$ $f o r t r a c i n g .$
Commented by ajfour last updated on 12/Dec/17

Commented by ajfour last updated on 12/Dec/17

$y^{2} = \frac{x^{2} (3 - x)}{x + 1} > 0$ $\Rightarrow (x - 3) (x + 1) < 0$ $s o x \in (- 1, 3]$ $a s x \to - 1, y \to \pm \infty$ $d o u b l e r o o t a t x = 0 .$ $s y m m e t r y a b o u t x - a x i s c o z o f y^{2} .$
Commented by rita1608 last updated on 13/Dec/17

$i t s a 10 m a r k q u e s t i o n p l s s s t a t e a l l$ $p r o p e r t i e s$
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