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Question Number 87050 by jagoll last updated on 02/Apr/20
whataretherootsofthesystemofequationxy+yx+1=43andx+y+xy=5?
Commented by john santu last updated on 02/Apr/20
⇒x+y+xy+1=6⇒x(y+1)=5−yx=5−yy+1(x+1)(y+1)=6x+1=6y+1⇒5−yy(y+1)+y(y+1)6=4330−6y+y2(y+1)2=8y(y+1)y4+2y3+y2−8y2−14y+30=0y4+2y3−7y2−14y+30=0
Commented by MJS last updated on 02/Apr/20
no‘‘nice″solutiony≈1.75925±.436230i∨y≈−2.75925±1.23214i
Commented by jagoll last updated on 02/Apr/20
thankyoumister
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