why the first ionisation(△H_(i1) )energy of Oxygen smaller than the second? A. Due to the nuclear charge B. Due to the distance of the electron from the nucleus C. Due to the effect of spin−pair repulsion D. Due to a shielding effect.


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Question Number 64101 by Rio Michael last updated on 13/Jul/19

$w h y t h e f i r s t i o n i s a t i o n (△ H_{i 1}) e n e r g y o f O x y g e n s m a l l e r$ $t h a n t h e s e c o n d ?$ $A . D u e t o t h e n u c l e a r c h a r g e$ $B . D u e t o t h e d i s t a n c e o f t h e e l e c t r o n f r o m t h e n u c l e u s$ $C . D u e t o t h e e f f e c t o f s p i n - p a i r r e p u l s i o n$ $D . D u e t o a s h i e l d i n g e f f e c t .$
Commented by ngahcedric last updated on 07/Dec/20

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