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Question Number 22769 by Bruce Lee last updated on 22/Oct/17

$$\mathbf{write}\mathbf{to}\mathbf{geometry}\mathbf{form}$$$$\frac{3}{5}+\frac{4}{5}\mathbf{i}$$$$$$$$\mathbf{help}\mathbf{plz}$$

Answered by $@ty@m last updated on 22/Oct/17

$$Let\frac{3}{5}+\frac{4}{5}\mathbf{i}=r\cos \theta +i.r\sin \theta$$$$\Rightarrow r\cos \theta =\frac{3}{5}\mathrm{\&}r\sin \theta =\frac{4}{5}$$$$\Rightarrow r=1\mathrm{\&}\theta ={\tan }^{-1}\frac{4}{3}$$$$\therefore \frac{3}{5}+\frac{4}{5}\mathbf{i}=\cos \theta +i.\sin \theta$$$$where\theta ={\tan }^{-1}\frac{4}{3}$$

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