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Question Number 85358 by jagoll last updated on 21/Mar/20

$$\sqrt[3]{\mathrm{x}}+\sqrt{\mathrm{x}}=12$$

Answered by john santu last updated on 21/Mar/20

$$x=t^6$$$$\Rightarrow t^2+t^3-12=0$$$$(t-2)(t^2+3t+6)=0$$$$\Rightarrow t=2\Rightarrow x=2^6=64$$$$\Rightarrow t=\frac{-3\pm i\sqrt{15}}{2}$$$$\Rightarrow x={\left(\frac{-3\pm i\sqrt{15}}{2}\right)}^6$$

Commented by john santu last updated on 21/Mar/20

$$hahaha...upsidedownsir$$

Commented by MJS last updated on 21/Mar/20

$$\mathrm{sorry},\mathrm{but}\mathrm{you}\mathrm{made}\mathrm{a}\mathrm{weird}\mathrm{mistake}$$$$x=t^6$$$$\Rightarrow t^3+t^2-12=0\Rightarrow t=2\Rightarrow x=2^6=64$$

Commented by MJS last updated on 21/Mar/20

$$\mathrm{yes},\mathrm{I}\mathrm{also}\mathrm{tend}\mathrm{to}\mathrm{this}\mathrm{kind}\mathrm{of}\mathrm{error}\mathrm{sometimes}$$

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