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Question Number 162715 by tounghoungko last updated on 31/Dec/21
∣∣x−1∣−5∣⩾2hassolutionsetisa⩽x⩽borx⩽c∪x⩾d.Finda+db+c.
Answered by bobhans last updated on 01/Jan/22
∣∣x−1∣−5∣⩾2⇒(∣x−1∣−7)(∣x−1∣−3)⩾0⇒∣x−1∣⩽3∪∣x−1∣⩾7⇒−2⩽x⩽4∪x⩽−6∪x⩾8{a=−2∧b=4c=−6∧d=8⇒a+db+c=6−2=−3
Answered by MJS_new last updated on 31/Dec/21
∣∣x−1∣−5∣⩾2(1)x⩾1⇒∣x−6∣⩾2(1.1)x⩾6⇒x−6⩾2⇒x⩾8(1.2)1⩽x<6⇒6−x⩾2⇒1⩽x⩽4(2)x<1⇒∣x+4∣⩾2(2.1)−4<x<1⇒x+4⩾2⇒−2⩽x<1(2.2)x⩽−4⇒−x−4⩾2⇒x⩽−6=====x⩽−6∨−2⩽x⩽4∨8⩽xa=−2,b=4,c=−6,d=8⇒a+db+c=−3
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