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Question Number 8262 by 666225 last updated on 04/Oct/16

∣x−1∣ < 2 ⇒ ∣x−3∣

x1<2x3

Commented by 123456 last updated on 04/Oct/16

∣x−1∣<2⇔−2<x−1<2  −2−2<x−3<2−2  −4<x−3<0  0<∣x−3∣<4

x1∣<22<x1<222<x3<224<x3<00<∣x3∣<4

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