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Question Number 145285 by SinNombre last updated on 03/Jul/21

x=2−2+2−2+2−…+2−2+2=2

x=2−2+2−2+2−…+2−2+2=2

Commented by phally last updated on 04/Jul/21

x_1 =2+2+2+...+2 {n+1} x_2 =−(2+2+2+...2){n} ⇒x_1 +x_2 =2

x1=2+2+2+...+2{n+1}x2=−(2+2+2+...2){n}⇒x1+x2=2

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