Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 119996 by behi83417@gmail.com last updated on 28/Oct/20

$$\{\begin{array}{l}{\mathit{x}}^3+{\mathit{y}}^2=\mathit{a}\\ {\mathit{x}}^2+{\mathit{y}}^3=\mathit{b}\end{array}[\mathit{s}\mathit{o}\mathit{l}\mathit{v}\mathit{e}\mathit{f}\mathit{o}\mathit{r}:\mathrm{x},\mathrm{y},\mathrm{a}\ne \mathrm{b}\in \mathbf{R}]$$

Answered by TANMAY PANACEA last updated on 28/Oct/20

$$x^6={(a-y^2)}^2$$$$x^6={(b-y^3)}^3$$$$a^2-2{ay}^2+y^4=b^3-3b^2{y}^3+3{by}^6-y^9$$$$y^9-3{by}^6+y^4+3b^3{y}^3-2{ay}^2-b^3=0$$$$\mathit{W}aitpls$$$$$$$$$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com