x^5 +ax^3 +bx^2 +cx+d=0 (x^2 +px+q)(x^3 +rx^2 +sx+t)=0 then elimating r,s,t pq(p^2 +a)+d=q(b+2pq) q^2 (p^2 +a)+dp=q(c+q^2 ) please try bringing into single variable sir...


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Question Number 65959 by ajfour last updated on 06/Aug/19

$x^{5} + {a x}^{3} + {b x}^{2} + c x + d = 0$ $(x^{2} + p x + q) (x^{3} + {r x}^{2} + s x + t) = 0$ $t h e n e l i m a t i n g r, s, t$ $p q (p^{2} + a) + d = q (b + 2 p q)$ $q^{2} (p^{2} + a) + d p = q (c + q^{2})$ $p l e a s e t r y b r i n g i n g i n t o s i n g l e$ $v a r i a b l e s i r . . .$
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