(x_C −h)^2 +3((s/2)−x_C )^2 = a^2 (x_A −h)^2 +3((s/2)+x_A )^2 = c^2 (x_C −x


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Question Number 56264 by ajfour last updated on 13/Mar/19

${(x_{C} - h)}^{2} + 3 {(\frac{s}{2} - x_{C})}^{2} = a^{2}$ ${(x_{A} - h)}^{2} + 3 {(\frac{s}{2} + x_{A})}^{2} = c^{2}$ ${(x_{C} - x_{A})}^{2} = b^{2} / 4 .$
Commented by MJS last updated on 12/Mar/19

$seems impossible$
Commented by ajfour last updated on 13/Mar/19

Commented by ajfour last updated on 13/Mar/19

$F i n d m a x i m u m a n d m i n i m u m$ $v a l u e o f e d g e l e n g t h s o f$ $c i r c u m s c r i b i n g e q u i l a t e r a l △ .$
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