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Question Number 10970 by Joel576 last updated on 04/Mar/17

$$x^{x^{x^{{\text{iddots}}^2}}}=2$$$$\mathrm{What}\mathrm{is}\mathrm{the}\mathrm{value}\mathrm{of}x?$$

Answered by ridwan balatif last updated on 04/Mar/17

$$\mathrm{we}\mathrm{know}{\mathrm{x}}^{{\mathrm{x}}^{{\mathrm{x}}^{{\mathrm{x}}^{{.}^{{.}^{...}}}}}}=2$$$$\mathrm{so}{\mathrm{x}}^{\left({\mathrm{x}}^{{\mathrm{x}}^{{\mathrm{x}}^{{\mathrm{x}}^{{.}^{..}}}}}\right)}=2$$$${\mathrm{x}}^2=2$$$$\mathrm{x}=\sqrt{2}$$

Commented by Joel576 last updated on 05/Mar/17

$$thankyouverymuch$$

Commented by Joel576 last updated on 05/Mar/17

$$thankyouverymuch$$

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