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Question Number 18299 by tawa tawa last updated on 18/Jul/17

$${\mathrm{x}}^{{\mathrm{x}}^{\mathrm{x}}}=2,\mathrm{find}\mathrm{x}$$

Commented by mrW1 last updated on 19/Jul/17

$$\mathrm{no}\mathrm{analytic}\mathrm{solution}$$$$\sqrt{2}<\mathrm{x}<2$$

Commented by tawa tawa last updated on 19/Jul/17

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

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