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Question Number 3930 by Filup last updated on 25/Dec/15

$$y=\frac{{\log }_e(\frac{x}{m}-sa)}{r^2}$$$${yr}^2={\log }_{\mathrm{e}}(\frac{x}{m}-sa)$$$$e^{{yr}^2}=\frac{x}{m}-sa$$$${me}^{rry}=x-mas$$$$$$$$\mathrm{Merry}\mathrm{christmas}\mathrm{everyone}!$$$$\mathrm{Let}\mathrm{our}\mathrm{venture}\mathrm{for}\mathrm{knowledge}\mathrm{continue}$$$$\mathrm{through}\mathrm{to}\mathrm{the}\mathrm{new}\mathrm{year}!$$

Commented by Yozzii last updated on 25/Dec/15

$$Sametoyou!$$

Commented by RasheedSindhi last updated on 25/Dec/15

$$\underset{\mathcal{CH}ri\mathcal{ST}ma\mathcal{S}}{{\mathcal{MERRY}}_{\mathcal{T}o}}\mathcal{YOU}{\mathcal{T}}_{\mathcal{OO}!}{!}^{!}$$

Commented by prakash jain last updated on 25/Dec/15

$$\left|\begin{array}{ccccccc}★& \mathcal{M}& ★& ★& ★& \mathcal{Y}& ★\\ ★& ★& \mathcal{E}& ★& \mathcal{R}& ★& ★\\ ⧫& ⧫& ⧫& \mathcal{R}& ⧫& ⧫& ⧫\\ ✠& \mathrm{♠}& \mathrm{♠}& ◼& \mathrm{♣}& \mathrm{♣}& ✠\\ ★& \mathbb{X}& -& \mathbb{M}& \mathbb{A}& \mathbb{S}& ★\end{array}\right|$$$$\wedge$$$$\wedge \wedge \wedge$$$$\wedge \wedge \wedge \wedge \wedge$$$$\wedge \wedge \wedge \wedge \wedge \wedge \wedge$$$$\wedge \wedge \wedge \wedge \wedge \wedge \wedge \wedge \wedge$$$$\parallel \parallel$$$$$$

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