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Question Number 18681 by Joel577 last updated on 27/Jul/17

$$y=\mid \sin x\mid +2$$$$y=\mid x\mid +2-\pi$$$$-\pi ⩽x⩽\pi$$$$\mathrm{Find}\mathrm{the}\mathrm{area}\mathrm{that}\mathrm{have}\mathrm{created}$$$$\mathrm{from}\mathrm{the}\mathrm{equations}\mathrm{above}$$

Answered by ajfour last updated on 27/Jul/17

Commented by ajfour last updated on 27/Jul/17

$${\int }_0^{\pi }\sin \mathrm{xdx}=(-\cos \mathrm{x}){\mid }_0^{\pi }=2$$$$\mathrm{Required}\mathrm{area}=2+2+\frac{1}{2}\left(2\pi \right)\left(\pi \right)$$$$={\pi }^2+4.$$

Commented by Joel577 last updated on 28/Jul/17

$$\mathrm{can}\mathrm{we}\mathrm{solve}\mathrm{this}\mathrm{without}\mathrm{graph}?$$

Commented by ajfour last updated on 28/Jul/17

$$\mathrm{one}\mathrm{way}\mathrm{or}\mathrm{another},\mathrm{more}\mathrm{or}\mathrm{less},$$$$\mathrm{the}\mathrm{same}\mathrm{thing}.$$

Commented by Joel577 last updated on 28/Jul/17

$$okay,thankyouverymuch$$

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